本文实例讲述了PHP将二维数组某一个字段相同的数组合并起来的方法。分享给大家供大家参考，具体如下：

例子：

array(3) {

[0]=>

array(16) {

["id"]=>

string(2) "42"

["uid"]=>

string(2) "14"

["euid"]=>

string(2) "56"

["did"]=>

string(1) "1"

["nid"]=>

string(1) "0"

["phonetime"]=>

string(10) "1443927600"

["createtime"]=>

string(10) "1443880619"

["type"]=>

string(1) "3"

["status"]=>

string(1) "0"

["atype"]=>

string(1) "1"

["mtype"]=>

string(1) "2"

["endtime"]=>

string(1) "0"

["time"]=>

string(10) "10月04日"

["date"]=>

string(6) "周日"

["uname"]=>

NULL

["album"]=>

string(0) ""

}

[1]=>

array(16) {

["id"]=>

string(2) "40"

["uid"]=>

string(2) "14"

["euid"]=>

string(2) "56"

["did"]=>

string(1) "1"

["nid"]=>

string(1) "0"

["phonetime"]=>

string(10) "1444359600"

["createtime"]=>

string(10) "1444268595"

["type"]=>

string(1) "3"

["status"]=>

string(1) "0"

["atype"]=>

string(1) "1"

["mtype"]=>

string(1) "2"

["endtime"]=>

string(1) "0"

["time"]=>

string(10) "10月09日"

["date"]=>

string(6) "周五"

["uname"]=>

NULL

["album"]=>

string(0) ""

}

[2]=>

array(16) {

["id"]=>

string(2) "43"

["uid"]=>

string(1) "2"

["euid"]=>

string(2) "56"

["did"]=>

string(1) "1"

["nid"]=>

string(1) "0"

["phonetime"]=>

string(10) "1444359620"

["createtime"]=>

string(10) "1444268595"

["type"]=>

string(1) "3"

["status"]=>

string(1) "0"

["atype"]=>

string(1) "1"

["mtype"]=>

string(1) "2"

["endtime"]=>

string(1) "0"

["time"]=>

string(10) "10月09日"

["date"]=>

string(6) "周五"

["uname"]=>

NULL

["album"]=>

string(0) ""

}

}

现在想要对这个二维数组下的元素，time相同的合并到同一数组下。想要的效果为：

array(2) {

["10月04日"]=>

array(1) {

[0]=>

array(16) {

["id"]=>

string(2) "42"

["uid"]=>

string(2) "14"

["euid"]=>

string(2) "56"

["did"]=>

string(1) "1"

["nid"]=>

string(1) "0"

["phonetime"]=>

string(10) "1443927600"

["createtime"]=>

string(10) "1443880619"

["type"]=>

string(1) "3"

["status"]=>

string(1) "0"

["atype"]=>

string(1) "1"

["mtype"]=>

string(1) "2"

["endtime"]=>

string(1) "0"

["time"]=>

string(10) "10月04日"

["date"]=>

string(6) "周日"

["uname"]=>

NULL

["album"]=>

string(0) ""

}

}

["10月09日"]=>

array(2) {

[0]=>

array(16) {

["id"]=>

string(2) "40"

["uid"]=>

string(2) "14"

["euid"]=>

string(2) "56"

["did"]=>

string(1) "1"

["nid"]=>

string(1) "0"

["phonetime"]=>

string(10) "1444359600"

["createtime"]=>

string(10) "1444268595"

["type"]=>

string(1) "3"

["status"]=>

string(1) "0"

["atype"]=>

string(1) "1"

["mtype"]=>

string(1) "2"

["endtime"]=>

string(1) "0"

["time"]=>

string(10) "10月09日"

["date"]=>

string(6) "周五"

["uname"]=>

NULL

["album"]=>

string(0) ""

}

[1]=>

array(16) {

["id"]=>

string(2) "43"

["uid"]=>

string(1) "2"

["euid"]=>

string(2) "56"

["did"]=>

string(1) "1"

["nid"]=>

string(1) "0"

["phonetime"]=>

string(10) "1444359620"

["createtime"]=>

string(10) "1444268595"

["type"]=>

string(1) "3"

["status"]=>

string(1) "0"

["atype"]=>

string(1) "1"

["mtype"]=>

string(1) "2"

["endtime"]=>

string(1) "0"

["time"]=>

string(10) "10月09日"

["date"]=>

string(6) "周五"

["uname"]=>

NULL

["album"]=>

string(0) ""

}

}

}

那么。。。代码很简单，没有想象的那么复杂，想要的结果是个三维数组

$result 为原二维数组

$res = array(); //想要的结果

foreach ($result as $k => $v) {

$res[$v['time']][] = $v;

}

希望本文所述对大家PHP程序设计有所帮助。